(3x^2+4x+5)(4x-5)=

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Solution for (3x^2+4x+5)(4x-5)= equation: 


Simplifying
(3x2 + 4x + 5)(4x + -5) = 0

Reorder the terms:
(5 + 4x + 3x2)(4x + -5) = 0

Reorder the terms:
(5 + 4x + 3x2)(-5 + 4x) = 0

Multiply (5 + 4x + 3x2) * (-5 + 4x)
(5(-5 + 4x) + 4x * (-5 + 4x) + 3x2 * (-5 + 4x)) = 0
((-5 * 5 + 4x * 5) + 4x * (-5 + 4x) + 3x2 * (-5 + 4x)) = 0
((-25 + 20x) + 4x * (-5 + 4x) + 3x2 * (-5 + 4x)) = 0
(-25 + 20x + (-5 * 4x + 4x * 4x) + 3x2 * (-5 + 4x)) = 0
(-25 + 20x + (-20x + 16x2) + 3x2 * (-5 + 4x)) = 0
(-25 + 20x + -20x + 16x2 + (-5 * 3x2 + 4x * 3x2)) = 0
(-25 + 20x + -20x + 16x2 + (-15x2 + 12x3)) = 0

Combine like terms: 20x + -20x = 0
(-25 + 0 + 16x2 + -15x2 + 12x3) = 0
(-25 + 16x2 + -15x2 + 12x3) = 0

Combine like terms: 16x2 + -15x2 = 1x2
(-25 + 1x2 + 12x3) = 0

Solving
-25 + 1x2 + 12x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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